Question 82

What is the distance between the points (4,8) and (-2,0)?

Solution

Distance between two points $$(x_1 , y_1)$$ and $$(x_2 , y_2)$$ = $$\sqrt{(y_2 - y_1)^2 + (x_2 - x_1)^2}$$

Now, distance between points (-2,0) and (4,8)

= $$\sqrt{(8 - 0)^2 + (4 + 2)^2} = \sqrt{(8)^2 + (6)^2}$$

= $$\sqrt{64 + 36} = \sqrt{100}$$

= $$10$$ units

=> Ans - (D)

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