Three bottles of equal capacity containing mixture of milk and water in ratio 2 : 5, 3 : 4 and 4 : 5 respectively. These three bottles are emptied into a large bottle. What will be the ratio of milk and water respectively in the large bottle?

Let the capacity of each bottle = 63 litres    [L.C.M.(7,7,9)]

Ratio of milk and water in the three bottles respectively = 2:5 , 3:4 and 4:5

Milk in 1st bottle = $$\frac{2}{(2+5)}\times63=18$$ litres

and water in 1st bottle = $$63-18=45$$ litres

Similarly, milk in 2nd bottle = $$\frac{3}{7}\times63=27$$ litres

 and water in 2nd bottle = $$63-27=36$$ litres

Similarly, milk in 3rd bottle = $$28$$ litres and water = $$35$$ litres

=> Total milk = $$18+27+28=73$$ litres

 and total water = $$45+36+35=116$$ litres

$$\therefore$$ Required ratio = $$\frac{73}{116}$$

=> Ans - (B)