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Study the table answer the given questions:
Percentage of marks obtained by six students A, B, C, D, E and F in Different subjects.

The average marks obtained by students A, C and D in Mathematics is what per cent less than the total marks obtained by student F in all the five subjects (correct to one decimal place)?
The total marks obtained by A, C and D in mathematics = 80+70+90 = 240%.
Average marks = 240/3 = 80% of 150 = 120.
Total marks obtained by F in all the subjects = 0.84*50 + 0.92*150 + 0.90*80 + 0.84*75 + 0.73*100 = 388.
The required percentage = $$\frac{388\ -\ 120}{388}\times\ 100\ \approx\ 69.1\%\ $$.
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