Question 80

ABC is a triangle, PQ is line segment intersecting AB in P and AC in Q and PQ II BC. The ratio of AP : BP = 3 : 5 and length of PQ is 18 cm. The length of BC is

Solution

$$\triangle APQ and \triangle ABC are similar triangles.$$

By similarity theorem ,

$$\frac{AP}{AB} = \frac{PQ}{BC}$$

$$ \frac{AP}{AP + BP} = \frac{PQ}{BC}$$

$$ \frac{3}{3 + 5} = \frac{18}{BC}$$

BC = 48 cm

So, the answer would be option b)48 cm

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