The lattice enthalpy and enthalpy of solution in water for solid NaCl are $$753\ \text{kJ mol}^{-1}$$ and $$5\ \text{kJ mol}^{-1}$$ respectively. If the solution enthalpies of $$\text{Na}^+$$ and $$\text{Cl}^-$$ are in the ratio $$6 \colon 5$$, the enthalpy of hydration of $$\text{Na}^+$$ ion is

A

$$408\ \text{kJ mol}^{-1}$$

B

$$-412\ \text{kJ mol}^{-1}$$

C

$$-408\ \text{kJ mol}^{-1}$$

D

$$-412 \text{ kJ mol}^{-1}$$