Solution
The numbers are of the form, $$(n^2-4)$$
$$(2)^2-4$$ = 0
$$(3)^2-4$$ = 5
$$(4)^2-4$$ = 12
$$(5)^2-4$$ = 21 $$\neq20$$
$$(6)^2-4$$ = 32
$$(7)^2-4$$ = 45
=> Ans - (C)
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