Question 79

$$2\frac{1}{3} + 3\frac{3}{4} \div \frac{3}{4} - 2\frac{1}{3}\left(6\frac{1}{2} - 2\frac{1}{4}\right) \div 2\frac{1}{4} =$$

Solution

$$\frac{7}{3}+\frac{\frac{15}{4}}{\frac{3}{4}}-\frac{\frac{7}{3}\left(\frac{17}{4}\right)}{\frac{9}{4}}$$

$$\frac{7}{3}+5-\frac{119}{27}$$

$$\frac{63}{27}+\frac{105}{27}-\frac{119}{27}=\frac{79}{27}$$


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