Solution
As per the given question,
$$p:q=7:9$$
Now, p=7x and q=9x
$$\Rightarrow \dfrac{(4p - 2q)}{(3p + q)}=\dfrac{4\times 7x-2\times 9x}{3\times 7x+9x}$$
$$\Rightarrow \dfrac{(4p - 2q)}{(3p + q)}=\dfrac{28x-18x}{21x+9x}$$
$$\Rightarrow \dfrac{(4p - 2q)}{(3p + q)}=\dfrac{10x}{30x}=\dfrac{1}{3}$$
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