Question 78

If $$\frac{1}{(tanA + cotA)}=x$$, then value of x is

Solution

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Expression : $$\frac{1}{(tanA + cotA)}=x$$

= $$1\div(tanA+cotA)$$

= $$1\div(\frac{sinA}{cosA}+\frac{cosA}{sinA})$$

= $$1\div(\frac{sin^2A+cos^2A}{sinAcosA})$$

= $$1\div(\frac{1}{sinAcosA})$$

= $$1 \times sinAcosA = sinAcosA$$

=> Ans - (A)

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