Question 78

Efficiency of A is twice as that of B. If they work together, they can complete a job in 18 days. If A alone does the job, in how many days he will complete the job?

Solution

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Let total work = 18 units

Let B's efficiency = $$x$$ units/day and A's efficiency = $$2x$$ units/day

According to ques, working together, they finish work in = $$(x+2x)\times18=18$$

=> $$3x=1$$

=> $$x=\frac{1}{3}$$

$$\therefore$$ Time taken by A alone to finish the work = $$\frac{18}{\frac{1}{3}}=54$$ days

=> Ans - (D)

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