Question 76

Mehdi can complete a work in 25 hours. If he is joined by Jahnavi who is 50% more efﬁcient, in what time will they together ﬁnish the work?

Solution

Let total work to be done = 50 units

Mehdi's efficiency = $$\frac{50}{25} = 2$$ units/hr

Jahnavi is 50% more efficient than Mehdi, => Jahnavi's efficiency = $$\frac{150}{100} \times 2 = 3$$ units/hr

=> Mehdi and Jahanavi 1 day's work = 2 + 3 = 5 units/hr

$$\therefore$$ Time taken by them to finish the work together = $$\frac{50}{5} = 10$$ hours

=> Ans - (B)

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