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If $$v = (x^2 + y^2 + z^2)^{\frac {-1}{2}}$$, then $$\frac{\partial^2 v}{\partial x^2} + \frac{\partial^2 v}{\partial y^2} + \frac{\partial^2 v}{\partial z^2}$$ is
$$ -\frac {1}{2}$$
$$-1$$
$$0$$
$$1$$
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