If $$\left(\sqrt[3]{\frac{3}{2}}\right)^x = \left(\frac{9}{4}\right)^{2x - 7}$$, then x =

A

$$\frac{7}{3}$$

B

$$\frac{21}{11}$$

C

$$\frac{14}{3}$$

D

$$\frac{42}{11}$$