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If $$f(x, y) = x^n . y^n$$ and $$f\left(4x, \frac{y}{2}\right) = k.f(x, y)$$ then k =
$$4n - \frac{m}{2}$$
$$2(n - m)$$
$$2^{2n - m}$$
$$2^{m - 2n}$$
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