If $$3x+5(4-3x)>2-4x<3x-\frac{x}{3}$$; then the value of x is

Expression 1 : 3x + 5(4 - 3x) > 2 - 4x

=> $$3x+20-15x$$ > $$2-4x$$

=> $$12x-4x$$ < $$20-2$$

=> $$8x$$ < $$18$$

=> $$x$$ < $$\frac{9}{4}$$ -----------(i)

Expression 2 : 2 - 4x < 3x - x/3

=> $$4x+3x-\frac{x}{3}$$ > $$2$$

=> $$\frac{20x}{3}$$ > $$2$$

=> $$x$$ > $$\frac{3}{10}$$ ----------(ii)

Combining inequalities (i) and (ii), we get : $$\frac{3}{10}$$ < $$x$$ < $$\frac{9}{4}$$

The only value that $$x$$ can take among the options = 2

=> Ans - (C)