A thief is stopped by a policeman from a distance of 400 metres. When the policeman starts the chase, the thief also starts running. Assuming the speed of the thief as 5 km/h and that of policeman as 9 km/h, how far the thief would have run, before he is over-taken by the policeman?

Since the thief is escaping from the police man, thus they both are running in same direction.

Speed of thief = 5 km/hr and speed of policeman = 9 km/hr

=> Relative speed = 9 - 5 = 4 km/hr

Distance between them = 400 metres = 0.4 km

=> Time taken = $$\frac{distance}{speed}$$

= $$\frac{0.4}{4} = \frac{1}{10}$$ hr

$$\therefore$$ Distance covered by thief before he was caught = $$5 \times \frac{1}{10}$$

= 0.5 km = 500 metres

=> Ans - (C)