Question 75

If the equations 6x - 5y + 11 = 0 and 15x + ky- 9 = 0 have no solution, then the
value of k is:

Solution

The correct option is C.
If two lines has no solution then lines are parallel.
So, $$\frac{a_{1}}{a_{2}}$$ = $$\frac{b_{1}}{b_{2}}$$ $$\ne$$ $$\frac{c_{1}}{c_{2}}$$

$$\Rightarrow$$ $$\frac{6}{15}$$ = $$\frac{-5}{k}$$

k = -12.5

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RRB ALP 21st Aug 2018 Shift-3

If the equations 6x - 5y + 11 = 0 and 15x + ky- 9 = 0 have no solution, then thevalue of k is:

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If the equations 6x - 5y + 11 = 0 and 15x + ky- 9 = 0 have no solution, then the
value of k is: