Solution
2r =h+$$\sqrt{r^{2}+h^{2}}$$
=> 2r-h=$$\sqrt{r^{2}+h^{2}}$$
=> $$(2r-h)^2$$=$$(r^{2}+h^{2})$$
=> $$4r^2+h^2-4rh$$=$$(r^{2}+h^{2})$$
=> $$3r^2$$=4rh
=>3r=4h
=> r:h=4:3
Create a FREE account and get:
- Free SSC Study Material - 18000 Questions
- 230+ SSC previous papers with solutions PDF
- 100+ SSC Online Tests for Free
