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Solution
2r =h+$$\sqrt{r^{2}+h^{2}}$$
=> 2r-h=$$\sqrt{r^{2}+h^{2}}$$
=> $$(2r-h)^2$$=$$(r^{2}+h^{2})$$
=> $$4r^2+h^2-4rh$$=$$(r^{2}+h^{2})$$
=>Â $$3r^2$$=4rh
=>3r=4h
=> r:h=4:3
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