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Instructions
In each of these question two equations I & II with variables a & b are given You have to solve both the equations to find the values of a & b
Mark answer if
a) a<b
b) $$a\leq b$$
c) relationship between a & b cannot be established
d) a>b
e) $$a\geq b$$
Solution
$$16a^{2}=1$$
Solving we get, a=-.25, a=+.25
$$3b^{2}+7b+2=0$$
Solving we get, b= -2. b = -1/3
Hence, a>b. Option D is correct.
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