Instructions

In each of these question two equations I & II with variables a & b are given You have to solve both the equations to find the values of a & b
Mark answer if
a) a<b

b) $$a\leq b$$

c) relationship between a & b cannot be established

d) a>b

e) $$a\geq b$$

Question 76

I.$$a^{2}+2a+1=0$$
II.$$b^{2}=\pm4$$

Solution

We can easily solve equation I to get a = -1
But we cannot solve $$b^{2}=\pm4$$. Square root of negative number is not a real number.
Hence, we cannot find a value of b. Therefore, we cannot establish a relationship between a and b.


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