Instructions

In each of these question two equations I & II with variables a & b are given You have to solve both the equations to find the values of a & b
Mark answer if
a) a<b

b) $$a\leq b$$

c) relationship between a & b cannot be established

d) a>b

e) $$a\geq b$$

Question 74

I.$$a^{2}+5a+6=0$$
II.$$b^{2}+7b+12=0$$

Solution

$$a^{2}+5a+6=0$$
i.e (a+2)(a+3)=0
i.e a=-2, a=-3

.$$b^{2}+7b+12=0$$
i.e (b+4)(b+3)=0
i.e b=-4, b=-3

Hence, we can deduce that $$a \geq b$$.
Therefore, option E is correct.


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