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If $$xy \neq 0$$ and $$x * y = 1 + \frac{1}{xy}$$, then $$\sum_{a =1}^{2020}(\frac{1}{a^{2}} * a)$$
2020 $$\times$$ 1011
2021 $$\times$$ 1011
2023 $$\times$$ 1010
2021 $$\times$$ 1010
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