If $$x \triangle y = \mid x \mid y+ x \mid y \mid - (x+y)$$ for $$x, y∈ℝ$$, then $$\frac{-3}{2} \triangle \frac{1}{2}=$$

A

1

B

$$\frac{-1}{2}$$

C

$$\frac{1}{2}$$

D

$$\frac{1}{4}$$