If $$x \downarrow y = (x + y) + (x - y)^2$$ and $$x \uparrow y = (x + y)^3 - (x - y)^3$$ then the value $$\frac{(0 \downarrow 1) \uparrow (0 \downarrow 1)}{(1 \uparrow 2) \downarrow (1 \uparrow 2)} =$$

A

$$\frac{8}{7}$$

B

$$\frac{15}{7}$$

C

$$\frac{14}{9}$$

D

$$\frac{13}{8}$$