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If $$ \sin x = \frac{m}{\sqrt{1 + m^2}} $$ then find $$ ' \tan x '$$
$$ \sqrt{1 + m^2} $$
$$ \frac{m^2 - 1 }{m ^ 2 + 1} $$
m
$$ \frac{m^2 }{1 + m ^ 2} $$
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