For two non-zero numbers m and n define * by:
$$m * n = \frac{1}{mn} + 1$$, then
$$\sum_{k=1}^{2018}\left(\frac{1}{k^2} * k\right) =$$

A

1008 X 2018

B

1009 X 2019

C

2017 X 2018

D

2018 X 2019