For the natural numbers $$x$$ and y, define
$$x * y = \sqrt{xy} + \frac{1}{\sqrt{xy}}$$ and $$x \odot y = \sqrt{xy} - \frac{1}{\sqrt{xy}}$$, then $$\frac{(3*4)*(3 \odot 4)}{(3*4)\odot(3 \odot 4)}$$ =

A

1

B

$$\frac{37}{36}$$

C

$$\frac{62}{61}$$

D

$$\frac{155}{131}$$