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Evaluate:$$(\sqrt{3}-\frac{1}{\sqrt{3}})^{2}$$
2$$\sqrt{3}$$
$$\frac{3}{4}$$
$$\frac{4}{\sqrt{3}}$$
$$\frac{4}{3}$$
The correct option is D.
$$\left({\sqrt{3}}-\frac{{1}}{\sqrt{3}}\right)^{2}$$
=$$\left(\frac{{3-1}}{\sqrt{3}}\right)^{2}$$
=$$\left(\frac{{2}}{\sqrt{3}}\right)^{2}$$
After squaring
=$$\left(\frac{{4}}{{3}}\right)$$
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