The dimensions of a rectangular plot is $$40m\times20m$$. A path is formed across the plot along the length and breadth with a uniform width of 2 meters. If the cot of forming, the path is Rs. 500 per sq.meter, the cost of laying that path (in Rs.) is

According to the question,

length of the path would be 40m and width of the path would be 2m by the length side(area of that path is$$=40×2=80m^2$$).

And ,length of the path would be 20m and width of the path would be 2m by the breadth side(area$$=20×2=40m^2$$).

If it cost 500 Rs. to laying the path, total cost of laying the path would be

$$=80×500+40×500=60000.$$

But,in corner a reapetated cost is taken during the path ,whose length and breadth would be of 2m respectively.

So,area of that portion is$$=2×2=4m^2.$$

So,cost of that path$$=4×500=2000Rs.$$

So,Total cost$$=60000-2000=58000.$$

A is correct choice.