Sanjya and Saumya together can finish a work in 9 days. Sanjya can do the same job on his own in 15 days. The same work Saumya can do by himself in:
Work done per unit by Saumya alone = $$\frac{1}{9}-\frac{1}{15}$$
= $$\frac{5-3}{45}=\frac{2}{45}$$
$$\therefore$$ Time taken by Saumya alone = $$\frac{45}{2}=22\frac{1}{2}$$ days
=> Ans - (C)
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