Question 73

$$(8-(28-53))\div(-4\times5-(-9))=?$$

Solution

$$(8-(28-53)) = 8-28+53 = 33$$
$$(-4\times5-(-9)) = -20+9 = -11$$
Therefore, $$(8-(28-53))\div(-4\times5-(-9))=\dfrac{33}{-11} = -3$$

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