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Question 73
10 years ago, the ages of A and B were in the ratio of 13: 17. 17 years from now the ratio of their ages will be 10: 11. What is the age of B at present ?
Solution
Let the present ages of A and B be x and y.
10 years ago, the ages of A and B were in the ratio of 13: 17 i.e $$\frac{x-10}{y-10}$$ = $$\frac{13}{17}$$
i.e 17x - 13y = 40
17 years from now the ratio of their ages will be 10: 11. i.e $$\frac{x+17}{y+17}$$ = $$\frac{10}{11}$$
i.e 10y-11x = 17
Simultaneously solving the two equation we get, x=23 and y=27 years.
Option C is correct answer.
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