Question 72

The value of $$27a^3 - 2\sqrt{2}b^3$$ is equal to:

Solution

$$27a^3 - 2\sqrt{2}b^3 = (3a - \sqrt{2}b)(9a^2 + 2b^2 + 6\sqrt{2}ab)$$

($$\because a^3 - b^3 = (a - b)(a^2 + ab + b^2)$$)

here,

a = 3a

b = $$\sqrt{2}b$$

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