The correct sequence of reactions which will yield 4-nitrobenzoic acid from benzene is

$$\text{CH}_3\text{Cl}$$; $$\text{HNO}_3$$ with $$\text{H}_2\text{SO}_4$$; $$\text{KMnO}_4$$ with $$\text{OH}^-$$

$$\text{HNO}_3$$ with $$\text{H}_2\text{SO}_4$$; $$\text{CH}_3\text{Cl}$$ with $$\text{AlCl}_3$$; $$\text{KMnO}_4$$ with $$\text{OH}^-$$

$$\text{CH}_3\text{Cl}$$ with $$\text{AlCl}_3$$; $$\text{KMnO}_4$$ with $$\text{OH}^-$$; $$\text{HNO}_3$$ with $$\text{H}_2\text{SO}_4$$

$$\text{CH}_3\text{Cl}$$ with $$\text{AlCl}_3$$; $$\text{HNO}_3$$ with $$\text{H}_2\text{SO}_4$$; $$\text{KMnO}_4$$ with $$\text{OH}^-$$