Question 72
If $$3x^2 + ax + 4$$ is perfectly divisible by $$x — 8,$$ then the value of $$a$$ is:
Solution
If $$3x^2 + ax + 4$$ is perfectly divisible by $$x — 8,$$ then x-8 is a factor and x = 8 should satisfy the inequality f(x) = 0.
$$3\left(8\right)^2+8a+4=0$$
==> 8a = -196
==> a = -24.5
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