E, F and G together can complete a work in 12 days. If E and F together can complete the same work in 30 days, then in how many days can G alone complete the same work?
LCM of 12 and 30 is 60. So we can assume the total work is 60 units.
E, F and G together can complete a work in 12 days.
The efficiency of E, F and G together = $$\frac{60}{12}$$ = 5 units/hour
If E and F together can complete the same work in 30 days.
The efficiency of EÂ and F together = $$\frac{60}{30}$$ = 2 units/hour
Number of days taken by G alone to complete the same work = $$\frac{60}{5-2}$$
=Â $$\frac{60}{3}$$
=Â 20 days
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