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$$\triangle H_{vap}^{o} = 30.8 kj mol^{-1}$$ and $$\triangle S_{vap}^{o}=87.2 j mol^{-1} K^{-1}$$ for benzene, what is the boiling poing of benzene? Assume that $$\triangle H_{vap}{0}$$ and $$\triangle S_{vap}{0}$$ are independent of temperature.
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