The banker's discount on a certain sum due 2 years hence is 11/10 of the true discount.The rate percentis
Let true discount T.D. be Re 1
=> B.D. = Rs. $$\frac{11}{10}=1.10$$
$$\therefore$$ Sum = $$\frac{(1.10\times1)}{(1.10-1)}=Rs.$$ $$11$$
=> S.I. on Rs. 11 for 2 years is Rs. 1.10
Let rate of interest be $$r\%$$
=> $$\frac{11\times r\times2}{100}=1.1$$
=> $$r=\frac{110}{22}=5\%$$
=> Ans - (C)
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