If $$x = (164)^{169} + (333)^{337} - (727)^{726}$$, then what is the units degit of x?
$$x = (164)^{169} + (333)^{337} - (727)^{726}$$
For the units digit of x,
= (unit digit)$$^{remainder}$$
Remainder = 169/4 = 1, 337/4 = 1, 726/4 = 2
Units digit of x = $$(4)^1 + (3)^1 - (7)^2$$
= 4 + 3 - 9 = -2
= 10 - 2 = 8
Units digit of x = 8
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