4 men and 5 women can complete a work in 15 days, whereas 9 men and 6 womencan doit in 10 days. To complete the same work in 7 days, how many women should assist 4 men?
Total wwork = men/women $$\times days \times h$$
ATQ,
$$(4m +Â 5w) \times 15 =Â (9m + 6w) \times 10$$
60m + 75w = 90m +Â 60w
15w = 30m
w = 2m
Let the x women should assist 4 men.
Now,
$$(4m + 5w) \times 15 =Â (4m + xw) \times 7$$
$$60m + 75w = 28m +Â 7xw$$
30w +Â 75w = 14w + 7xw
7x = 91
x = 13
$$\therefore$$ 13Â women should assist 4 men.
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