Given equation;

$$\frac{1}{6} + \frac{1}{12} + \frac{1}{20} + \frac{1}{30} + \frac{1}{42} + \frac{1}{56}$$

= ($$\frac{1}{2}$$ - $$\frac{1}{3}$$ + $$\frac{1}{3}$$ - $$\frac{1}{4}$$ + $$\frac{1}{4}$$ - $$\frac{1}{5}$$ + $$\frac{1}{5}$$ - $$\frac{1}{6}$$ + $$\frac{1}{6}$$ - $$\frac{1}{7}$$ + $$\frac{1}{7}$$ - $$\frac{1}{8}$$)

= $$ \frac{1}{2} - \frac{1}{8} = \frac{6}{16} = \frac{3}{8} $$

Hence, Option (B) is the correct answer.