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Solution
We have, $$\mid x^2 - x - 6 \mid = x + 2$$
=> |(x-3)(x+2)|=x+2
For x<-2, (3-x)(-x-2)=x+2
=> x-3=1 =>x=4 (Rejected as x<-2)
For -2$$\le\ $$x<3, (3-x)(x+2)=x+2 =>x=2,-2
For x$$\ge\ $$3, (x-3)(x+2)=x+2 =>x=4
Hence the product =4*-2*2=-16
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