Question 69

Two chords AB and CD of a circle are produced to intersect each other at a point P outside the circle. If AB = 7 cm, BP = 4.2 cm and PD = 2.8 cm, then the length of CD is:

Solution

AB = 7 cm, BP = 4.2 cm and PD = 2.8 cm

By the property,

PA $$\times PB = PC \times PD$$

(PA = AB + BP = 7 + 4.2 = 11.2 cm)

11.2 $$\times 4.2 = PC \times 2.8

PC = 16.8 cm

CD = PC - PD = 16.8 - 2.8 = 14 cm

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