Question 69

The value of $$\frac{sin^263^\circ+sin^227^\circ}{cos^217^\circ+cos^273^\circ}$$ is

Solution

Expression : $$\frac{sin^263^\circ+sin^227^\circ}{cos^217^\circ+cos^273^\circ}$$

= $$(sin^263^\circ+sin^2(90-63)^\circ)\div(cos^217^\circ+cos^2(90-17)^\circ)$$

Using, $$sin(90^\circ-theta)=cos \theta$$ and $$cos(90^\circ-\theta)=sin \theta$$

= $$(sin^263^\circ+cos^263^\circ)\div(cos^217^\circ+sin^217^\circ)$$

Using, $$(sin^2\theta+cos^2\theta=1)$$

= $$(1)\div(1)=1$$

=> Ans - (B)

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