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A walks 15 m in front and 15 m to the right then every time turning to his left, he walks 10, 20 and 30 m respectively. How far is he now from his starting point?
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The person started walking from S and stopped at E.
To calculate SE, we need to find the length of hypoteneuse in the triangle SAE where SA = 5 m and AE = 30 - 15 - 10 = 5 m.
Length of SE = $$\sqrt{\ 5^2+5^2}=5\sqrt{\ 2}$$ m.
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