Question 69

A train crosses a 600 metres long platform in 50 seconds. It crosses another 900 metres long platform in 60 seconds. What are the length and the speed ofthe train? (Assuming the train is going at constant speed)

Solution

speed = $$\frac{length of train + length of platfom}{time}$$

In both. The case speed of train will be same so,

$$\frac{L+ length of platfom}{time}$$ = $$\frac{ L+ length of platfom}{time}$$

$$\frac{L+ 600}{50}$$ = $$\frac{ L+ 900}{60}$$

L= 900 m

Speed= $$\frac{900+ 600}{50}$$ 

  =30m/s

Change into km/hr

30$$\times \frac{18}{5}$$

= 108 km/hr


Create a FREE account and get:

  • Free SSC Study Material - 18000 Questions
  • 230+ SSC previous papers with solutions PDF
  • 100+ SSC Online Tests for Free

cracku

Boost your Prep!

Download App