Question 70

The Bar graph given below presents the marks (out of 100) obtained by 10 students in a subject.

The average of marks obtained by S3 and S5 is what percent less than the marks obtained by S9?

Solution

S3 = 87

S5 = 99

avg = $$\frac{99+87 }{2}$$ = 93

S9=100

so,

$$\frac{ 100-93}{100}\times100$$ = 7%


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