The Bar graph given below presents the marks (out of 100) obtained by 10 students in a subject.
The average of marks obtained by S3 and S5 is what percent less than the marks obtained by S9?
S3 = 87
S5 = 99
avg = $$\frac{99+87 }{2}$$ = 93
S9=100
so,
$$\frac{ 100-93}{100}\times100$$ = 7%
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