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Question 67
What is the value of $$\left(\frac{4 \div 2 + 2 - \frac{1}{2} \times \frac{1}{4}}{8 - 3 \div \frac{1}{4} + 6}\right)$$?
Solution
Solving the numerator,
$$\dfrac{4}{2}+2-\dfrac{1}{2}\times\dfrac{1}{4}$$
= $$2+2-\dfrac{1}{8}$$
= $$4-\dfrac{1}{8} = \dfrac{32-1}{8}$$
= $$\dfrac{31}{8}$$
Solving the denominator,
$$8-3\times4+6 = 8-12+6 = 2$$
Therefore, $$\left(\dfrac{4 \div 2 + 2 - \dfrac{1}{2} \times \dfrac{1}{4}}{8 - 3 \div \dfrac{1}{4} + 6}\right) = \dfrac{(\dfrac{31}{8})}{2} = \dfrac{31}{16}$$
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