Question 67

The value of $$26.4 \times 12.5 + \sqrt{22^{2} + 20 + 11^{2}} - 31$$ is:

Solution

= $$26.4 \times 12.5 + \sqrt{22^{2} + 20 + 11^{2}} - 31$$

= $$26.4\times12.5+\sqrt{484+20+121}-31$$

= $$26.4\times12.5+\sqrt{625}-31$$
= $$330+25-31$$
= $$330-6$$
= 324

Share on Whatsapp Share on Whatsapp

Create a FREE account and get:

Free SSC Study Material - 18000 Questions
230+ SSC previous papers with solutions PDF
100+ SSC Online Tests for Free

Follow us on

Boost your Prep!

Download App