The sum of two angles of a triangle is 116° and their difference is 24°. The measure of smallest angle of the triangle is
Let the angles of the triangle be $$\alpha,\beta$$ and $$\theta$$
Here, $$\alpha+\beta=116^\circ$$ --------(i)
and $$\alpha-\beta=24^\circ$$ -----------(ii)
Adding equations (i) and (ii)
=> $$2\alpha=116+24=140^\circ$$
=> $$\alpha=\frac{140}{2}=70^\circ$$
Substituting it in equation (i), => $$\beta=116-70=46^\circ$$
Also, in a triangle, $$\alpha+\beta+\theta=180^\circ$$
=> $$70^\circ+46^\circ+\theta=180^\circ$$
=> $$\theta=180-116=64^\circ$$
Thus, the smallest angle = $$\beta = 46^\circ$$
=> Ans - (C)
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